Question

Tolong bantuin yah nomor 3 & 4 aja,pakai cara yah
makasih

Answer 1

Verified answer

Jawab

(3) luas permukaan bandul = luas 1/2 bola+ luas selimut kerucut
r = 7
t = 24
s = √(t²+r²)= √(7²+24²) = √625 = 25

L = 1/2 (4 π r² ) + (π r s)
L = 2 π r² + π r s
L = π r  ( 2r + s)
L = (22/7) (7)( 2(7) + 25))
L = 22 (14 + 25)
L = 22(39)  = 858

(4)  kerucut
Keliling alas = 62,8
2 π r = 62.8
r = 62,8 / (2)(3,14)
r = 62,8 /6,28
r = 10
t = 18
Volume = 1/3 π r² t
V = 1/3 (3,14)(10²)(18) = 1.884

Answer 2

Menurut daya pikir saya dengan memakai cara yg paling simpel dalam mtk:
3. L.P.Bandul= 22. 39= 858 cm
4. V.kerucut = 1/3. Πr^2.t
= 1/3. 3,14, 10^2. 18
= 1/3. 314. 18
= 1/3. 6652
= 1884 cm^2

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