Question

tolong bantuin ya makasihhh​

Answer 1

Jawaban dan penyelesaian terlampir

Answer 2

Penjelasan dengan langkah-langkah:

Bantu Jawab

1) Panjang semua rusuk

PQ = SR = TU = WS → 12 cm

PS = QR = VU = TW → 3 cm

PT = QU = RV = SW → 4 cm

2) Luas PQRS = Luas TUVW

= 12 × 3

= 36 cm²

Luas QRUV = Luas PSWT

= 3 × 4

= 12 cm²

Luas PQUT = Luas SRVW

= 12 × 4

= 48 cm²

3) Diagonal TQ = PU = SV = RW

= √(12²+4²)

= √(144+16)

= √160

= √16×10

= 4√10 cm

Diagonal UR = VQ = PW = TS

= √(4²+3²)

= √(16+9)

= √(25)

= 5 cm

Diagonal PR = SQ = TV = WV

= √(12²+3²)

= √(144+9)

= √(153) cm

4) Luas bidang Diagonal PRVT = WSQU

= √153 × 4

= 4√153 cm²

Luas bidang Diagonal PSVU = QRWT

= 4√10 × 3

= 12√10 cm²

Luas bidang diagonal TUSR = WVPQ

= 12 × 5

= 60 cm²