no 9)
Sin A = de/mi = 1/3
sa = √(3²-1²) = √8 = 2√2
Cos A = sa/mi = 2√2/3
Tan A = de/sa = 1/2√2
jadi :
6 cos A tan A =
6(2√2)/3.(1/(2√2)) =
12√2 / 6√2 =
2
no 10)
Cos C = sa/mi = 5/13
de = √(13²-5²) =√144 = 12
cosec A = 1/sin A = mi/de = 13/5
jadi
13 cosec A cos C =
13.13/5.5/13 =
13
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
no 9)
Sin A = de/mi = 1/3
sa = √(3²-1²) = √8 = 2√2
Cos A = sa/mi = 2√2/3
Tan A = de/sa = 1/2√2
jadi :
6 cos A tan A =
6(2√2)/3.(1/(2√2)) =
12√2 / 6√2 =
2
no 10)
Cos C = sa/mi = 5/13
de = √(13²-5²) =√144 = 12
cosec A = 1/sin A = mi/de = 13/5
jadi
13 cosec A cos C =
13.13/5.5/13 =
13