Question

Tolong bantuin dong,nomer 4-12:") pentingg kak:")))

Answer 1

Data untuk HCl :
V = 50 mL = 0,05 L
P = 75 cmHg = 0,986 atm
T = 25⁰C = 298⁰K

* Mencari mol HCl :
P x V = n x R x T
0,986 x 005 = n x 0,082 x 298
0,049 = 24,436n
n = 0,002 mol

* Mencari Molaritas HCl :
M = mol/Volume
M = 0,02/0,6
M = 0,0033 M

* Mencari [H⁺]
[H⁺] = M x Valensi asam
[H⁺] = 0,0033 x 1
[H⁺] = 3,33 x 10⁻³

* Mencari pH
pH = -log [H⁺]
pH = -log [3,33 x 10⁻³]
pH = 3 - log 3,33

Jadi, pH larutan adalah 3 - log 3,33

Ok?