integral Tertentu
₀¹∫ (1 - 2x³)/(x³) dx
= ₀¹∫ (1- 2x³). (x⁻³) dx = ₀¹ ∫ (x⁻³ - 2) dx
= [ -1/ (2x²) - 2x]¹₀
= -1 (1/2 - 1/0) - 2(1- 0)
= - 1 (1/2 - ~ ) - 2
= divergen
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maaf bila keliru
integral Tertentu
₀¹∫ (1 - 2x³)/(x³) dx
= ₀¹∫ (1- 2x³). (x⁻³) dx = ₀¹ ∫ (x⁻³ - 2) dx
= [ -1/ (2x²) - 2x]¹₀
= -1 (1/2 - 1/0) - 2(1- 0)
= - 1 (1/2 - ~ ) - 2
= divergen