Question

Tolong bantuannya. kalo mau kasih caranya juga. pliss no 41,42,43.

Answer 1

41. Anggap titik tengah (T)
Kel ketupat = 4s
68 = 4s
s = 68/4 = 17
ambil salah satu segitiga, KTN (KN=17cm NT=8cm)
KT^2 = KN^2 - NT^2
= 17^2 - 8^2
= 289 - 64
= 225
KT = 15cm
KM = 2 x KT = 2 x 15 = 30cm (C)

42. pake perbandingan
AB/SR = CD/PQ
16/12 = CD/6
8/6 = CD/6
CD = 8cm (B)

43. jumlah sudut segitiga selalu 180°, jadi
40° + x + 30° + 2x + 20° = 180°
90° + 3x = 180°
3x = 180° - 90°
3x = 90°
x = 30°
sudut ABD berpelurus dg sudut CBD, sehingga
ABD = BCD + BDC
= 40° + 2(30°) + 20°
= 40° + 60° + 20°
= 120° (C)