Question

Tolong bantuan nya nomor 4

Answer 1

Verified answer

Titik potong terhadap sumbu x diperoleh jika y = 0
(x - 5)^2 + y^2 = 25
(x - 5)^2 + 0^2 = 25
(x - 5) = ± 5
x = 5 ± 5
x = 10 atau x = 0 => batas integral

(x - 5)^2 + y^2 = 25
y^2 = 25 - (x - 5)^2
V = π (batas 0 - 10) ∫ y^2 dx
= π (batas 0 - 10) ∫ 25 - (x - 5)^2 dx
= π (25x - 1/3 (x - 5)^3) | batas 0 - 10
= π [(25 (10) - 1/3 (10 - 5)^3) - (25(0) - 1/3 (0 - 5)^3))
= π [250 - 125/3 - (0 + 125/3)]
= (250 - 250/3) π
= (750 - 250)/3 π
= (500π)/3

Atau bisa juga dengan rumus volume bola dengan r = 5
V = 4/3 π r^3 = 4/3 π (5)^3 = 4/3 π (125) = (500π)/3