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= 200 gr
= 30°C
= 100 gr
= 90°C
= 1 kal/gr°C
Ditanya : Suhu akhir campuran T....?
Jawab :
=
. . ΔT1 = . . ΔT2
200 . 1 . (T - 30) = 100 . 1 . (90 - T)
200T - 6000 = 9000 - 100
300T = 15000
T = 50°C