Question

Tolong bantu ya nomor 21 dan 23 please

Answer 1

No.21

3x + 5y - 6 = 0
m= -3/5
persamaan pada titik (2,-4)
y-y1 = m(x-x1)
y+4 = -3/5 (x-2)
5y + 20 = -3x + 6
3x + 5y + 14 = 0
Jawaban : B

Answer 2

21. m=
3x+5y-6=0
5y=-3x+6
y=-3/5x+6/5
m=-3/5

y+4=m(x-2)
y+4=-3/5(x-2)
y=-3/5x+6/5-4
5y=-3x+6-4(5)
5y=-3x+6-20
5y=-3x-14
3x+5y+14=0. (B)

23.bx+ay=ab
4y+2x=8
4y+2x-8=0--->:2
2y+x-4=0 (A)