Penjelasan dengan langkah-langkah:
BD² = 15²-9²
BD² =225-81 = 144
BD = √144 = 12cm
BC² = 12²+35²
BC²=144+1225 = 1369
BC= √1369 = 37cm
Luas segitiga = ½×a×t
= ½×44×12
= 22×12 = 264cm²
a. gunakan rumus Pythagoras
[tex]bd = \sqrt ba^{2} + \sqrt ad^{2} \\ = \sqrt{15}^{2} + \sqrt{ {9}^{2} } \\ = 15 + 9 \\ = 24[/tex]
b. masih menggunakan rumus Pythagoras
[tex]bc = \sqrt {bd}^{2} + \sqrt{ {dc}^{2} } \\ = \sqrt{ {24}^{2} } + \sqrt{ {35}^{2} } \\ = 24 + 32 \\ = 56[/tex]
c.
L=1/2×a×t
L=1/2×44×24
L=22×24
L=528 cm²
maaf jika salah
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Verified answer
Penjelasan dengan langkah-langkah:
BD² = 15²-9²
BD² =225-81 = 144
BD = √144 = 12cm
BC² = 12²+35²
BC²=144+1225 = 1369
BC= √1369 = 37cm
Luas segitiga = ½×a×t
= ½×44×12
= 22×12 = 264cm²
a. gunakan rumus Pythagoras
[tex]bd = \sqrt ba^{2} + \sqrt ad^{2} \\ = \sqrt{15}^{2} + \sqrt{ {9}^{2} } \\ = 15 + 9 \\ = 24[/tex]
b. masih menggunakan rumus Pythagoras
[tex]bc = \sqrt {bd}^{2} + \sqrt{ {dc}^{2} } \\ = \sqrt{ {24}^{2} } + \sqrt{ {35}^{2} } \\ = 24 + 32 \\ = 56[/tex]
c.
L=1/2×a×t
L=1/2×44×24
L=22×24
L=528 cm²
Penjelasan dengan langkah-langkah:
maaf jika salah