Question

Tolong bantu ya....... :)​

Answer 1

<AQC = 46°

Penjelasan dengan langkah-langkah:

sudut berpenyiku = 90°

<AQC + <BQC = 90°

(6x + 4)° + (5x + 9)° = 90°

6x° + 5x° + 4° + 9° = 90°

11x° + 13° = 90°

11x° = 90° - 13°

11x° = 77°

x = [tex]\displaystyle\sf~\frac{77}{11} [/tex]

x = 7°

maka,

<AQC = (6x + 4)°

<AQC = (6(7) + 4)°

<AQC = (42 + 4)°

<AQC = 46°