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Massa (m) = 500 g → 0,5 kg
Kalor (Q) = 84 kJ → 84.000 J
Suhu Awal (T1) = 30°C
Kalor jenis air (c) = 4200 J/kg°C
Ditanya : Suhu akhir setelah dipanaskan (T2) ..?
Jawab :
→ Q = m.c.∆t
→ Q = m.c. (T2 - T1)
→ 84.000 J = 0,5 kg x 4200J/kg°C . (T2 - 30°C)
→ 84.000 J = 2100 J . (T2- 30°C)
→ 84.000 J = 2100T2 - 63.000
→ 84.000 + 63.000 = 2100 T2
→ 147.000 = 2100 T2
→ T2 = 147.000 / 2100
→ T2 =70°C [ Jawaban]
Note :
1 kg = 1000 gram
1 kJ = 1000 Joule
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