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f(x) = x²-4x
g(x) = (3x-5)/(x-2)
Ditanya
( f ¤ g)(x) = ?
( f ¤ g)(x) = f[(3x-5)/(x-2)]
= [(3x-5)/(x-2)]² - 4[(3x-5/(x-2)]
= [ (3x -5)²/(x-2)²] - [ (12x -20)/(x-2)]
= [ (3x -5)²/(x-2)²] - [ (12x -20)(x-2)/(x-2)²]
= [ (3x -5)² - (12x -20)(x-2)] /(x-2)²
= [ ( 9x² - 30x + 25 -(12x² -44x+40)]/(x-2)²
= (9x² - 30x + 25 -12x² +44x - 40)]/(x-2)²
= (-3x² +14x -15)/(x-2)²