Question

Tolong bantu pakek cara ya no 5

Answer 1

H(t) = 100t - 5t^2
H(t) = - 5t^2 + 100t

Cara 1)
H(t) = - 5t^2 + 100t
a = - 5, b = 100, c = 0

t maks = - b/2a
= - 100/2(-5)
= - 100/-10
=10 s

H(t) = (b^2 - 4ac) /-4a
H(t) = (100^2 - 4(-5)(0))/-4(-5)
H(t) = 10000/20 = 500 m

Cara 2) turunan
H(t) = - 5t^2 + 100t
H'(t) = - 10t + 100
Agar bernilai maksimum, maka H'(t) = 0
0 = - 10t + 100
10t = 100
t = 10

H(t) = - 5t^2 + 100t
Kita substitusikan untuk t = 10
H(10) = - 5(10^2) + 100(10)
H(10) = - 500 + 1000 = 500 m

Semoga membantu :D