Question

tolong bantu now ngasal​

Answer 1

Verified answer

Diketahui :

Bangun = Tabung

Volume = 990 cm³

L. alas = 110 cm²

Ditanya :

Tinggi tabung?

Diketahui rumus :

• L. alas = π × r²
• [tex] \tt {r}^{2} = \frac{L.alas}{\pi} [/tex]
• V = π × r² × t
• [tex] \tt t = \frac{V}{\pi \times {r}^{2}}[/tex]

Penyelesaian :

Langkah Cepat

→ t = V ÷ L. alas

→ t = 990 cm³ ÷ 110 cm²

→ t = 9 cm

Langkah panjang

• Mencari r

→ r² = La/π

→ [tex] \tt {r}^{2} = \frac{110 ~ {cm}^{2}}{\frac{22}{7}} [/tex]

→ [tex] \tt {r}^{2} = 110 \div \frac{22}{7} [/tex]

→ [tex] \tt {r}^{2} = 110 \times \frac{7}{22} [/tex]

→ [tex] \tt {r}^{2} = \frac{770}{22} [/tex]

→ [tex] \tt {r}^{2} = 35 [/tex]

→ r = √35

• Mencari t

→ t = V/(π × r²)

→ [tex] \tt t = \frac{990}{\frac{22}{7} \times {(\sqrt{35})}^{2}} [/tex]

→ [tex] \tt t = \frac{990}{\frac{22}{7} \times 35 } [/tex]

→ [tex] \tt t = \frac{990}{\frac{770}{7}} [/tex]

→ [tex] \tt t = \frac{990}{110} [/tex]

→ 9 cm

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