Tolong bantu nomer 7&8 pakai cara penyelesaiannya terima kasih
Syubbana
No 7 cos sdt terbesar = (2²+3²-4²) / (2.2.3) = (4+9-16) / (12) = -3/12 = -1/4
no 8 a) panjang rusuk = ³√216 = 6 cm b) panjang diagonal ruang = r√3 = 6√3 cm c) luas permukaan kubus = 6.6² = 216 cm²
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5dregensleyer
Soal nomer 8 panjang rusuk volume = s³ 216 = s³ ∛216 = s 6 = s panjang diagonal ruang d = s√3 = 6√3 cm luas permukaan Lp = 6 x s² = 6 x 6 x 6 = 216 cm²
cos sdt terbesar = (2²+3²-4²) / (2.2.3)
= (4+9-16) / (12)
= -3/12
= -1/4
no 8
a) panjang rusuk = ³√216
= 6 cm
b) panjang diagonal ruang
= r√3
= 6√3 cm
c) luas permukaan kubus
= 6.6²
= 216 cm²
panjang rusuk
volume = s³
216 = s³
∛216 = s
6 = s
panjang diagonal ruang
d = s√3
= 6√3 cm
luas permukaan
Lp = 6 x s²
= 6 x 6 x 6
= 216 cm²