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Sisi depan (de) = a
Sisi miring (mi) = 1
Sisi samping (sa) = √(1^2 - a^2) = √(1 - a^2)
Karena π/2 < x < π => dikuadran 2 maka nilai cos dan Tan : negatif
Cos x = -sa/mi = -√(1 - a^2)/1 = -√(1 - a^2) x √(1 - a^2)/√(1 - a^2)
= - (1 - a^2)/√(1 - a^2) = (a^2 - 1) / √(1 - a^2)
Tan x = -de/sa = - a/(√1 - a^2)
Cos x - Tan x
= (a^2 - 1)/√(1 - a^2) - (-a)/√(1 - a^2)
= (a^2 + a - 1)/√(1 - a^2) .................... (A)