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rA=(4,5)m=4i+5j
rB=(6,3)m =6i+3j
Δt=2s
Ditanyakan:
-vektor Δr?
-Δrt?
-vektor Δv?
-Δvt
Dijawab:
-vektor Δr
Δx=(ri₂-ri₁)+(rj₂-rj₁)
Δr =rB-rA
=(6i-4i)+(3j-5j)
=2i-2j m
-besar resultan Δrt
|Δrt|=√(Δri²+Δrj²)
=√(2²+(-2)²)
=√(4+4)
=√8
=2√2 meter
-vektor Δv
Δv= Δr
Δt
=(2i-2j)
2-0
=i-j m/s
-besar resultan Δvt
|Δvt|=√(Δvi²+Δvj²)
=√(1²+1²)
=√2 m/s
Cheers :D