Question

Tolong bantu no. 18
Makasihh

Answer 1

Verified answer

Persamaan Garis

Melalui (0,a) dan (b,0) :
ax + by = a × b

•••
Melalui (0,-4) dan (6,0)
-4x + 6y = -24
m1 = -(-4)/6 = 2/3

tegaklurus ---> m2 = -1/m1 = -3/2

persamaan garis dg m = m2 = -3/2 melalui (x1,y1) = (0,-4) :
y - y1 = m(x - x1)
y + 4 = -3/2 x
2y + 8 = -3x
3x + 2y + 8 = 0 ✔

Answer 2

Verified answer

Garis k melalui (6 , 0) dan (0 , -4)

mₖ = Δy/Δx
mₖ = (-4 - 0) / (0 - 6)
mₖ = -4 / -6
mₖ = ⅔

Garis k dan garis n tegak lurus , shg
mₖ • mₙ = -1
⅔ • mₙ = -1
mₙ = - ³/₂

Garis n melalui (0 , -4)

Maka
y - y₁ = m(x - x₁)
y + 4 = - ³/₂ x [kali -2 kedua ruas]
-2y - 8 = 3x
3x + 2y + 8 = 0 [C]