~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Diket : panjang awal dawai, L = 80 cm = 0,8 m panjang akhir dawai, L' = 83 cm = 0,83 m pertambahan panjang dawai, ΔL = 0,03 m diameter, d = 1 mm = 10⁻³ m Modulus Young, E = 2,5 x 10¹¹ N/m²
Tanya : Gaya, F = __?
Jawab :
E = (F/A) / (ΔL/L) E = (F.L) / ( A.ΔL) E = (F.L) / ( π/4.d².ΔL)
Verified answer
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Diket :
panjang awal dawai, L = 80 cm = 0,8 m
panjang akhir dawai, L' = 83 cm = 0,83 m
pertambahan panjang dawai, ΔL = 0,03 m
diameter, d = 1 mm = 10⁻³ m
Modulus Young, E = 2,5 x 10¹¹ N/m²
Tanya :
Gaya, F = __?
Jawab :
E = (F/A) / (ΔL/L)
E = (F.L) / ( A.ΔL)
E = (F.L) / ( π/4.d².ΔL)
F = (E.π/4.d².ΔL) / L
F = (E.π.d².ΔL) / 4L
F = (2,5 x 10¹¹.π.(10⁻³)².0,03) / 4.(0,8)
F = 7,5.π x 10³ / 3,2
F = 2,34375.π x 10³
F = 7,359375 x 10³ N
Jawaban : E
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