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setimbang : 0,4 mol. 0,2. 0,2
Kp = mol senyawa/mol total x tekanan total
1) Kp PCl5 = 0,4/0,8 x 4 = 1/2 x 4 = 2 atm
2) Kp Pcl 3 = 0,2/0,8 x 4 = 1/4 x 4 = 1 atm
3) Kp Cl2 = 0,2/0,8 x 4 = 1/4 x 4 = 1 atm
Kp pada reaksi = [PCl3][Cl2]/ [PCl5] = 1.1/2 = 1/2
18. reaksi penguraian : 2NH3(g) -> N2(g) + 3H2(g)
Kc = mol senyawa/ mol total x volume total
1) Kc NH3 = 8/14 x 2 = 16/14 = 8/7
2) Kc N2 = 2/14 x 2 = 4/14 = 2/7
3) Kc H2 = 4/14 x 2 = 8/14 = 4/7
Kc pada reaksi = [N2][H2]³/ [NH3]²
= [2/7][4/7]³ = [2/7][64/343] = [2/7][343/49] = 2
________. ________
[8/7]². [64/49]