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(n+1)!/ ( n+1-3)! = n!/ (n-4)!
(n+1)! / (n-2)! = n! /( n-4)!
(n-2)! (n-1) (n) (n+1)/ (n-2)! = (n-4)! (n-3)(n-2)(n-1)(n)/ (n-4)!
n(n-1)(n+1) = (n-3)(n-2)(n-1)(n)
(n+1) = (n-3)(n-2)
n+1 = n² -5n +6
n² -6n +5 = 0
(n-5)(n-1) = 0
n =5 atau n =1