Materi : Garis dan Sudut
Konsep Penyiku ( 90° )
x + 28° + 6x - 15° = 90°
7x = 90° - 13°
7x = 77°
x = 11°
∠SQT = ( x + 28° ) = 39°
∠TQR = ( 6x - 15° ) = 51°
6x - 2 + 5x + 11 + 7x + 9 = 90°
18x + 18 = 90°
18x = 72°
x = 4°
Hasil / Result :
∠DAE = ( 6x - 2 ) = 24 - 2 = 22°
∠CAD = ( 5x + 11 ) = 20 + 11 = 31°
∠BAC = ( 7x + 9 ) = 28 + 9 = 37°
Semoga bisa membantu
[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
1) x + 28° + 6x - 15° = 90°
(1 + 6)x + (28 - 15)° = 90°
7x + 13° = 90°
7x = (90 - 13)°
7x = 77
x = (77/7)°
x = (11/1)°
MAKA :
SQT
= (11 + 28)°
= 39°
TQR
= (6 × 11 - 15)°
= (66 - 15)°
= 51°
2) 6x - 2 + 5x + 11 + 7x + 9 = 90°
(6 + 5 + 7)x + (11 - 2 + 9)° = 90°
(11 + 7)x + (9 + 9)° = 90°
18x + 18° = 90°
18x = (90 - 18)°
x = (72/18)°
x = 4/1
DAE :
= (6 × 4 - 2)°
= (24 - 2)°
= 22°
CAD :
= (5 × 4 + 11)°
= (20 + 11)°
= 31°
BAC :
= (7 × 4 + 9)°
= (28 + 9)°
= 37°
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Materi : Garis dan Sudut
Soal Nomor 1
Konsep Penyiku ( 90° )
x + 28° + 6x - 15° = 90°
7x = 90° - 13°
7x = 77°
x = 11°
∠SQT = ( x + 28° ) = 39°
∠TQR = ( 6x - 15° ) = 51°
Soal Nomor 2
Konsep Penyiku ( 90° )
6x - 2 + 5x + 11 + 7x + 9 = 90°
18x + 18 = 90°
18x = 72°
x = 4°
Hasil / Result :
∠DAE = ( 6x - 2 ) = 24 - 2 = 22°
∠CAD = ( 5x + 11 ) = 20 + 11 = 31°
∠BAC = ( 7x + 9 ) = 28 + 9 = 37°
Semoga bisa membantu
[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
Verified answer
1) x + 28° + 6x - 15° = 90°
(1 + 6)x + (28 - 15)° = 90°
7x + 13° = 90°
7x = (90 - 13)°
7x = 77
x = (77/7)°
x = (11/1)°
x = 11°
MAKA :
SQT
= (11 + 28)°
= 39°
TQR
= (6 × 11 - 15)°
= (66 - 15)°
= 51°
2) 6x - 2 + 5x + 11 + 7x + 9 = 90°
(6 + 5 + 7)x + (11 - 2 + 9)° = 90°
(11 + 7)x + (9 + 9)° = 90°
18x + 18° = 90°
18x = (90 - 18)°
18x = 72°
x = (72/18)°
x = 4/1
x = 4°
MAKA :
DAE :
= (6 × 4 - 2)°
= (24 - 2)°
= 22°
CAD :
= (5 × 4 + 11)°
= (20 + 11)°
= 31°
BAC :
= (7 × 4 + 9)°
= (28 + 9)°
= 37°