Question

tolong bantu jawab yh kk pliss....​

Answer 1

Penjelasan dengan langkah-langkah:

3. sudut prs = 3x°

sudut qrs = (5x + 20°)

nilai x

<prs + <qrs = 180°

3x + 5x + 20 = 180°

8x = 180 - 20

8x = 160°

x = 20°

sudut prs

= 3x

= 3(20°)

= 60°

sudut qrs

= 5x + 20

= 5(20) + 20

= 100 + 20

= 120°

4. sudut poq = 2x°

sudut qor = 3x°

sudut ros = 85°

a. nilai x

<poq + <qor + <ros = 180°

2x + 3x + 85 = 180°

5x = 180 - 85

5x = 95

x = 19°

b. besar poq

= 2x

= 2(19)

= 38°

c. besar qor

= 3x

= 3(19)

= 57°

d. besar rop

= 2x + 3x

= 5x

= 5(19)

= 95°

Answer 2

Verified answer

sudut

soal 1

∠PRS + ∠QRS = 180°

3x + 5x + 20° = 180°

8x = 160°

x = 20°

∠PRS = 3x = 3 × 20° = 60°

∠QRS = 5x + 20° = 5 × 20° + 20° = 120°

•

soal 2

∠POQ + ∠QOR + ∠ROS = 180°

2x + 3x + 85° = 180°

5x = 180° - 85°

x = 95°/5

x = 19°

koreksi

bukan ∠RPQ tapi ∠ROQ

∠ROQ = 3x = 3 × 19° = 57°

∠POQ = 2x = 2 × 19° = 38°