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y1=y2
x²= 4
x²-4=0
(x-2)(x+2)=0
x-2=0
x=2
x+2=0
x=-2
integral x²-4 batas atas 2 bawah -2 dx
[x³/3 -4x]²-2
[2³/3 -4(2)] - [ (-2)³/3 +4(-2)]
[8/3-8] - [ -8/3 -8)
8/3+8/3 -8-8
16/3 -16
= 16-48/3
= -32/3
jawabanya 32/3 # mungkin luas tandanya negatif bisa kita balik jadi 4x-x³/3