Question

Tolong bantu jawab ya.... :)

Answer 1

1) int (2x+3)(x-1) dx
= int  (2x² + x - 3) dx
= 2/3 x³ + 1/2 x² - 3x + C

2) int 6x(3x²+2)³ dx
misal u = 3x² + 2
du = 6x dx
= int u³ du
= 1/4 u^4 + C
= 1/4 (3x² + 2)^4 + C

3) int [0,pi/2] sin³xcosx dx
misal u = sinx
du = cosx dx
= int [0,pi/2] u du
= [1/2 u²] [0,pi/2]
= [1/2 sin²x] [0,pi/2]
= (1/2 sin²(pi/2)) - (1/2 sin²(0))
= 1/2

4) y = mx - 5
melalui (3,7), artinya
7 = m(3) - 5
7 + 5 = 3m
3m = 12
m = 12/43
m = 4