Question

Tolong bantu jawab soal nomor 5 ya...

Answer 1

∫(4,0) √(x²+9) x dx
misal u=x²+9
du/dx=2x
du=2x dx
x dx = ½ du
∫ √u ½ du
=½ ∫ u^½ du
=½.⅔√u³ + c
=⅓√u³ + c
=⅓√(x²+9)³ + c
masukkan batas
[⅓√(x²+9)³](4,0)
=[⅓√(4²+9)³] - [⅓√(0²+9)³]
=(125/3) - (27/3)
=98/3
=32 ⅔