Jawab:
Penjelasan dengan langkah-langkah:
y = x²-3x+3
y' = 2x-3
a. tegak lurus y = x+6 --> m1 = 1
m1.m2 = -1
m2 = -1
cari koordinat titik singgung :
2x-3 = -1
x = 1
y = (1)²-3(1)-3 = -5
maka PGS :
y-b = m(x-a)
y+5 = -(x-1)
y = -x-4
b. sejajar y = 1-5x --> m1 = -5
m1 = m2
m2 = -5
2x-3 = -5
x = -1
y = (-1)²-3(-1)-3 = 1
y-1 = -5(x+1)
y = -5x-4
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Jawab:
Penjelasan dengan langkah-langkah:
y = x²-3x+3
y' = 2x-3
a. tegak lurus y = x+6 --> m1 = 1
m1.m2 = -1
m2 = -1
cari koordinat titik singgung :
2x-3 = -1
x = 1
y = (1)²-3(1)-3 = -5
maka PGS :
y-b = m(x-a)
y+5 = -(x-1)
y = -x-4
b. sejajar y = 1-5x --> m1 = -5
m1 = m2
m2 = -5
cari koordinat titik singgung :
2x-3 = -5
x = -1
y = (-1)²-3(-1)-3 = 1
maka PGS :
y-b = m(x-a)
y-1 = -5(x+1)
y = -5x-4