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kurva y = 2x²
tik potong garis dan kurva
2x² = 1- x
2x² +x - 1 = 0
(2x-1)(x+1) = 0
x = 1/2 atau x = -1
x= 1/2, y = 1/2
mengelilingi sumbu y
batas intergral y = 0 sd y = 1/2
x+y = 1 --> x = 1- y
y = 2x² --> x² = 1/2 y
V = π ₀¹/² ∫ (1-y)² -(1/2 y) dy
V = π ₀ ¹/²∫ 1- 2y + y² - 1/2 y dy
V = π ₀ ¹/² ∫ y² - ⁵/₂ y + 1 dy
V = π [ ¹/₃ y³ - ⁵/₄ y² + y ]¹/² ₀
V = π [ ¹/₃(¹/₈) - ⁵/₄(¹/₄) + (¹/₂)]
V = π [¹/₂₄ - ⁵/₁₆+ ¹/₂]
V = π [¹¹/₄₈]