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diketahui
m = 500 g = 0,5 kg
c air = 1 kal/g = 1 kkal/kg
ΔT = 72 - 0 = 72°C
Ditanya : Kalor, Q(CD)
Penyelesaian
Q(CD) = m.c air.ΔT
Q(CD) = 0,5*1*72
Q(CD) = 36 kkal