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Penjelasan dengan langkah-langkah:
V E K T O R
9. A(1, –2, –1)
B(4, 1, –1)
C(2, 0, 1)
u = AB = (3, 3, 0)
v = BC = (–2, –1, 2)
u.v = –6–3+0
u.v = –9
|u| = √(3²+3²) = 3√2
|v| = √[(–2)²+(–1)²+2²) = √9 = 3
cos a = u.v
|u||v|
cos a = –9
3.3√2
9√2
a = 135° atau 225°
10. A(1, –2, –1)
B(5, 0, –1)
u = BC = (–3, 0, 2)
v = AC = (1, 2, 2)
u.v = 1.(–3)+2.0+2.2
u.v = –3+0+4 = 1
|v|² = [√(1²+2²+2²)]²
|v|² = [√(1+4+4)]²
|v|² = [√9]²
|v|² = 9
w = u → v
w = u.v (AC)
|v|²
w = 1 ( 1, 2, 2)
9
w = (1/9, 2/9, 2/9)
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Cara terlampir...
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..
Penjelasan dengan langkah-langkah:
V E K T O R
9. A(1, –2, –1)
B(4, 1, –1)
C(2, 0, 1)
u = AB = (3, 3, 0)
v = BC = (–2, –1, 2)
u.v = –6–3+0
u.v = –9
|u| = √(3²+3²) = 3√2
|v| = √[(–2)²+(–1)²+2²) = √9 = 3
cos a = u.v
|u||v|
cos a = –9
3.3√2
cos a = –9
9√2
cos a = –½√2 ✔
a = 135° atau 225°
10. A(1, –2, –1)
B(5, 0, –1)
C(2, 0, 1)
u = BC = (–3, 0, 2)
v = AC = (1, 2, 2)
u.v = 1.(–3)+2.0+2.2
u.v = –3+0+4 = 1
|v|² = [√(1²+2²+2²)]²
|v|² = [√(1+4+4)]²
|v|² = [√9]²
|v|² = 9
w = u → v
w = u.v (AC)
|v|²
w = 1 ( 1, 2, 2)
9
w = (1/9, 2/9, 2/9)
w = i + 2j + 2k ✔
9 9 9