Materi : Trigonometri
AD : BD : AB = √3 : 1 : 2
AD : BD = √3 : 1
AD/3 = √3/1
AD = 3 × √3
AD = 3√3 cm
CD : BD : BC = 1 : √3 : 2
CD : BD = 1 : √3
CD/3 = 1/√3
CD = 3 × √3/3
CD = √3 cm
AC = AD + CD = 3√3 + √3 = 4√3 cm
Lingkaran/Sisi = 360°/6 = 60°
Maka Radiusnya adalah 10 cm, Karena segitiga sama sisi yaitu 60° , 60°, 60°.
L = ½ . r . r . Sin ∅
L = ½ . 10 . 10 . Sin 60°
L = ½ . 100 cm² . √3/2
L = 50 cm² . √3/2
L = 25√3 cm²
6L = 25√3 cm² . 6
6L = 150√3 cm²
Semoga bisa membantu
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Materi : Trigonometri
Soal Nomor 13
Panjang Sisi AD
AD : BD : AB = √3 : 1 : 2
AD : BD = √3 : 1
AD/3 = √3/1
AD = 3 × √3
AD = 3√3 cm
Panjang Sisi CD
CD : BD : BC = 1 : √3 : 2
CD : BD = 1 : √3
CD/3 = 1/√3
CD = 3 × √3/3
CD = √3 cm
Panjang Sisi AC
AC = AD + CD = 3√3 + √3 = 4√3 cm
Soal Nomor 14
Nilai Sudut/Sisi
Lingkaran/Sisi = 360°/6 = 60°
Maka Radiusnya adalah 10 cm, Karena segitiga sama sisi yaitu 60° , 60°, 60°.
Luas Satu Sisi
L = ½ . r . r . Sin ∅
L = ½ . 10 . 10 . Sin 60°
L = ½ . 100 cm² . √3/2
L = 50 cm² . √3/2
L = 25√3 cm²
Luas Segi Enam
6L = 25√3 cm² . 6
6L = 150√3 cm²
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]