Jawaban:
C. 210 mm
Penjelasan dengan langkah-langkah:
Diketahui :
PR = 29 cm = 290 mm
QR = 20 cm = 200 mm
Ditanya :
PQ = ?
Jawab :
[tex]pq \: = \: \sqrt{pr^{2} \: - qr^{2} } \\ = \sqrt{290^{2} - 200^{2} } \\ = \sqrt{84100 - 40000 } \\ = \sqrt{44100} = 210 \: mm[/tex]
RQ = 20 cm
PR = 29 cm
[tex]\tt PQ^2=PR^2-RQ^2\\\\PQ^2=29^2-20^2\\\\PQ^2=841-400\\\\PQ=21^2\\\\PQ=21~cm\\\\PQ=21\times 10\\\\PQ=210~mm~(C)[/tex]
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Verified answer
Jawaban:
C. 210 mm
Penjelasan dengan langkah-langkah:
Diketahui :
PR = 29 cm = 290 mm
QR = 20 cm = 200 mm
Ditanya :
PQ = ?
Jawab :
[tex]pq \: = \: \sqrt{pr^{2} \: - qr^{2} } \\ = \sqrt{290^{2} - 200^{2} } \\ = \sqrt{84100 - 40000 } \\ = \sqrt{44100} = 210 \: mm[/tex]
Penjelasan dengan langkah-langkah:
RQ = 20 cm
PR = 29 cm
[tex]\tt PQ^2=PR^2-RQ^2\\\\PQ^2=29^2-20^2\\\\PQ^2=841-400\\\\PQ=21^2\\\\PQ=21~cm\\\\PQ=21\times 10\\\\PQ=210~mm~(C)[/tex]