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B : C= 2 : 5
Selisih= 28
Jumlah A + B= ?
A : B
B : C
3 : 4 |1 => 3 : 4
2 : 5 |2 => 4 : 10
Maka:
A : B : C= 3 : 4 : 10
Selisih A dan C= 28
Selisih= 10 - 3= 7
maka:
Banyak kelereng A:
3/7 × 28
3 × 4
12 kelereng
Banyak kelereng B:
4/3 × 12
4 × 4
16 kelereng
Maka:
A + B= 12 + 16
= 28
Jadi, jumlah kelereng A dan B adalah 28.
B:C = 2:5 ; 2C = 5B, C = 5B/2 = 2,5B
C-A = 28
2,5B - 0,75B = 28
7/4B = 28
B = 16
A = 3/4 × 16 = 12
A + B = 12 + 16 = 28