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Verified answer
Bab Sistem Persamaan Linear Kuadrat Dua Variabely = x^2
x^2 + y^2 = 1
x^2 + y^2 = 1
y + y^2 = 1
y^2 + y - 1 = 0
Cek diskriminan
a = 1, b = 1, c = -1
D = (1)^2 - 4(1)(-1)
D = 1 + 4
D = 5
Berarti persamaan memiliki 2 penyelesaian
y1,2 = (-(1) +- √(1^2 - 4(1)(-1)))/2(1)
y1,2 = (-1 +- √5)/2
y1 = (-1 + √5)/2 ; y2 = (-1 - √5)/2
y = x^2
x = √y
x1 = √y1
x1 = √((-1 + √5)/2)
x2 = √y2
x2 = √((-1 - √5)/2)
HP = {((-1 + √5)/2, √((-1 + √5)/2)) ; ((-1 - √5)/2 , √((-1 - √5)/2))}