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Mol =
=
=
=
=2,5 Mol
PV = nRT
V =
=
=12,3 Liter
Jawab No.2
Cara coba-coba:
H2SO4 + Al(OH)3 → Al2(SO4)3 + H2O
3 2 1 6
Cara substitusi:
aH2SO4 + bAl(OH)3 → cAl2(SO4)3 + dH2O
H : 2a + 3b = 2d
S : a = 3c
O : 4a + 3b = 12c + d
Al : b = 2c
Misal: c = 1, maka: a = 3; b = 2
2a + 3b = 2d
2x3 + 3x2 = 2xd
D=6
Jadi, a=3; b=2; c=1; d=6
mol C2H6 = massa/Mr = 75/30 = 2,5 mol
V = nRT/P = 2,5x0,0821x300/5 = 12,315 liter
2. 3 H2SO4 + 2 Al(OH)3 --> Al2(SO4)3 + 6 H2O