Question

Tolong banget No 25 dan 26 :)
#Makasih

Answer 1

25.C
26.B
maaf kalau salah

Answer 2

Diket
TA = 60'A
taA = 100A
tbA = -20'A
taB = 80'B
tbB = -10'B
Dit: TB......?
TA - taB/ taA - taA = TB - tbB/taB - tbA
60 - (-20)/100 - (-20) = TB - (-10)/80 - (-10)
60+20/100+20 = TB + 10/80+10
80/120 = (TB + 10)/90
120(TB + 10) = 90x80
120TB + 1200 = 7200
120 TB = 7200 - 1200
120TB = 6000
TB = 6000/120
TB = 50'B(A)

2. Diket: es
m = 100 garam = 0,1 kg
t awal = -10'c
t akhir = 100'c
Dit: Kalor yg diterima (Q).....?
Q1 = m.c.(t2-t1)
Q1 = 0,1x2100x(0-(-10))
Q1 = 0,1x2100x10
Q1 = 2100 J

Q2 = m.L
Q2 = 0,1x336.000
Q2 = 33600 J

Q3 = m.c.(t2-t1)
Q3 = 0,1x4200x(100-0)
Q3 = 0,1x4200x100
Q3 = 42000

jadi Qtotal = Q1+Q2+Q3
Q = 2100+33600+42000
Q = 77700 J
Q = 77,7 kJ(D)