Question

Tlong kerjakan dg caranya yg sya lingkari plisss

Answer 1

2a) Mr O2 = 32
mol O2 = 0,16/32 = 0,005 mol

2b) Mr Ba = 137, P = 31, O = 16
Ba3(PO4)2
= (137 x 3)+(31 x 2)+(16 x 8)
= 411 + 62 + 128
= 601
mol Ba3(PO4)2 = 10,02/601 = 0.017 mol

3) 0,4 mol H2S
a) m = Mr x mol
m = 34 x 0,4
m = 13,6 gram

b) JP = mol x 6,02 x 10^23
JP = 0,4 x 10^23 x 6,02
JP =  2,408 x 10^23

5) 9,2g NO2
a) JP = mol x 6,02 x 10^23
JP = 9,2/46 x 6,02 x 10^23
JP = 1,204 x 10^23

b) Keadaan standar = STP
Vol = 0,2 mol x 22,4L
Vol = 4,46L

Semoga membantu :)
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