Tlong jawabin yg B,C Ddong.... Question from @Ana453

MathTutor Soal b pada penyebutnya seharusnya x²-11x+28. Jadi,

$\frac{x^2-49}{x^2-11x+28}\\= \frac{(x-7)(x+7)}{(x-7)(x-4)}\\= \frac{x+7}{x-4}$

$\frac{x^2-1}{(1+xy)^2-(x+y)^2} \\= \frac{x^2-1}{1+2xy+x^2y^2-x^2-2xy-y^2} \\= \frac{x^2-1}{1+x^2y^2-x^2-y^2}\\= \frac{x^2-1}{1-y^2+x^2(y^2-1)}\\ =\frac{x^2-1}{y^2-1(x^2-1)}\\= \frac{1}{y^2-1}$

$\frac{(a^2-1)+(a^2+2a+1)}{(a^2+2a+1)(a^2-1)}\\= \frac{2a^2+2a}{(a+1)(a+1)(a^2-1)}\\= \frac{2a(a+1)}{(a+1)(a+1)(a^2-1)}\\= \frac{2a}{(a+1)(a^2-1)}$

Semangat!

1 votes Thanks 0

nadiaananda B. Sepertinya salah soal.. ini saya ganti (x² - 12x + 28) dengan (x² - 11x + 28) ya..

(x² - 49)/(x² - 11x + 28)
= (x + 7)(x - 7)/(x - 7)(x - 4)
= (x + 7)/(x - 4)

Kalau soal benar dan tidak diganti, soal sudah tidak bisa disederhanakan lagi :)
c. (x² - 1)/[(1 + xy)² - (x + y)²]
= (x² - 1)/(1 + 2xy + x²y² - x² - 2xy - y²)
= (x² - 1)/(-x² - y² + x²y² + 1)
= (x² - 1)/(x² - 1)(y² - 1)
= 1/(y² - 1)

1 votes Thanks 0

Tlong jawabin yang b,c

Me podrían decir que es un software para gestión estudiantil

0,80,03x+0,80,035(12000-x) = 300

Recommend Questions

Life Enjoy

Get in touch

Social