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F(0) = k . 2^(b(0)) = 7
k . 2^0 = 7
k . 1 = 7
jadi, k = 7
melewati titik (1,56)
F(x) = k . 2^(bx)
F(x) = 7 . 2^(bx)
F(1) = 7 . 2^(b(1)) = 56
7 . 2^b = 56
2^b = 8
2^b = 2^3
jadi, b = 3
jadi, F(x) = 7 . 2^(3x)
boleh tinggal dilanjutin sendiri ya? :-)
gapapa kan? hhehhe
soalnya rada sulit jawab dari hp :-) maaf