Jawaban:
1). PQ=16 ; QR= 30 ; PR = ?
[tex] {pr}^{2} = {qr}^{2} + {pq}^{2} \\ {pr}^{2} = {30}^{2} + {16}^{2} \\ {pr}^{2} = 900 + 256 \\ {pr}^{2} = 556 \\ pr = \sqrt{556 } \\ pr = \sqrt{4 \times 139} \\ pr = 2 \sqrt{139} [/tex]
2). ST = 5 ; SU =13 ; TU= ?
[tex] {tu}^{2} = {su}^{2} - {st}^{2} \\ {tu}^{2} = {13}^{2} - {5}^{2} \\ {tu}^{2} = 169 - 25 \\ {tu}^{2} = 144 \\ tu = \sqrt{144} \\ tu = 12[/tex]
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Jawaban:
1). PQ=16 ; QR= 30 ; PR = ?
[tex] {pr}^{2} = {qr}^{2} + {pq}^{2} \\ {pr}^{2} = {30}^{2} + {16}^{2} \\ {pr}^{2} = 900 + 256 \\ {pr}^{2} = 556 \\ pr = \sqrt{556 } \\ pr = \sqrt{4 \times 139} \\ pr = 2 \sqrt{139} [/tex]
2). ST = 5 ; SU =13 ; TU= ?
[tex] {tu}^{2} = {su}^{2} - {st}^{2} \\ {tu}^{2} = {13}^{2} - {5}^{2} \\ {tu}^{2} = 169 - 25 \\ {tu}^{2} = 144 \\ tu = \sqrt{144} \\ tu = 12[/tex]