Jawaban:
a. rumus phytagoras
[tex] {a}^{2} + {a}^{2} = {c}^{2} \\ {x}^{2} + {12}^{2} = {20}^{2} \\ {x}^{2} + 144 = 400 \\ {x}^{2} = 400 - 144 \\ {x}^{2} = 256 \\ x = \sqrt{256} \\ x = 16[/tex]
b. mencari sisi tegak pada segitiga yang kecil
menggunakan rumus phytagoras juga
[tex] {a}^{2} + {b}^{2} = {c}^{2} \\ {5 }^{2} + {b}^{2} = {13}^{2} \\25 + {b}^{2} = 169 \\ {b}^{2} = 169 - 25 \\ b \: = \sqrt{144} \\ = 12mm[/tex]
lalu mencari sisi miring pada segitiga yang besar menggunakan rumus phytagoras
[tex] {?}^{2} + {?}^{2} = {c}^{2} \\ {35}^{2} + {12}^{2} = {x}^{2} \\ 1.225 + 144 = {c}^{2} \\ 1.369 = {x}^{2} \\ {x}^{2} = 1.369 \\ x \: = 37 \: mm[/tex]
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Jawaban:
a. rumus phytagoras
[tex] {a}^{2} + {a}^{2} = {c}^{2} \\ {x}^{2} + {12}^{2} = {20}^{2} \\ {x}^{2} + 144 = 400 \\ {x}^{2} = 400 - 144 \\ {x}^{2} = 256 \\ x = \sqrt{256} \\ x = 16[/tex]
b. mencari sisi tegak pada segitiga yang kecil
menggunakan rumus phytagoras juga
[tex] {a}^{2} + {b}^{2} = {c}^{2} \\ {5 }^{2} + {b}^{2} = {13}^{2} \\25 + {b}^{2} = 169 \\ {b}^{2} = 169 - 25 \\ b \: = \sqrt{144} \\ = 12mm[/tex]
lalu mencari sisi miring pada segitiga yang besar menggunakan rumus phytagoras
[tex] {?}^{2} + {?}^{2} = {c}^{2} \\ {35}^{2} + {12}^{2} = {x}^{2} \\ 1.225 + 144 = {c}^{2} \\ 1.369 = {x}^{2} \\ {x}^{2} = 1.369 \\ x \: = 37 \: mm[/tex]