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Tugu kecil = d = 0,56, maka r = 0,28
tinggi = 0,5 m
Tugu besar = d = 0,84, maka r = 0,42
tinggi = 1,5 m
maka :
LP tugu kecil = 2 x π x r ( r + t)
= 2 x 22/7 x 0,28 (0,28+ 0,5)
= 44/7 x 0,28 x 0,78
= 1,3728
LP tugu besar = 2 x π x r ( r + t)
= 2 x 22/7 x 0,42 (0,42+ 1,5)
= 44/7 x 0,42 x 1,92
= 44/7 x 0,8064
= 5,0688
maka LP total = 1,3728 + 5,0688 = 6,4416 m = 644,16 (D)