Matriks
Sifat :
A = BC
det A = det B × det C
|A| = |B| × |C|
det = determinan
no. 4
det M = |M| = 2.5 - 3(-3) = 10 + 9 = 19
det N = 2.2 - 1.1 = 4 - 1 = 3
N = x . M
det X = det N / det M
|X| = 3/19
Nilai det X = |X| = 3/19.
•
no. 5
det K = |K| = xy - 3(-1) = xy + 3
det L = |L| = 5.3 - 2(-5) = 15 + 10 = 25
det (KL) = -425
|K| . |L| = -425
(xy + 3)(25) = -425
xy + 3 = -425/25
xy = -17 - 3
xy = -20
Nilai xy adalah (-20).
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Verified answer
Matriks
Sifat :
A = BC
det A = det B × det C
|A| = |B| × |C|
det = determinan
no. 4
det M = |M| = 2.5 - 3(-3) = 10 + 9 = 19
det N = 2.2 - 1.1 = 4 - 1 = 3
N = x . M
det X = det N / det M
|X| = 3/19
Nilai det X = |X| = 3/19.
•
no. 5
det K = |K| = xy - 3(-1) = xy + 3
det L = |L| = 5.3 - 2(-5) = 15 + 10 = 25
det (KL) = -425
|K| . |L| = -425
(xy + 3)(25) = -425
xy + 3 = -425/25
xy = -17 - 3
xy = -20
Nilai xy adalah (-20).