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74u-32u-2u=40u
Ca
CaO+H₂O=Ca(OH)₂
ponieważ Me(OH)2 ma masą 74u, to sam metal (Me) ma masę:
74 - (2*17) = 74 - 34 = 40 u
40u-> Ca
CaO + H2O -> Ca(OH)2