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m = (y₂ - y₁) / (x₂ - x₁)
= (-8 + 4) / (2 - 5)
= -4/-3
= 4/3
titik A (5, - 4) dan C (k, 12) berada digaris yg sama
m = (y₂ - y₁) / (x₂ - x₁)
4/3 = (12 + 4) / (k - 5)
4/3 = 16 / (k - 5)
4(k - 5) = 3 × 16
4k - 20 = 48
4k = 48 + 20
k = 68/4
k = 17 titik C (17,12)
b. AP = BP
P adalah titik tengah
P (x,y) = (x₁ + x₂)/2 , (y₁ + y₂)/2
= (5 + 2)/2 , (-4 - 8)/2
= 7/2 , -12/2
= 3,5 , -6
titik P (3,5 , -6)
persamaan titik P (7/2 , -6) melelui titik (0,3)
(y - y₁) / (y₂ - y₁) = (x - x₁) / (x₂ - x₁)
(y + 6) / (3 + 6) = (x - 7/2) / (0 - 7/2)
(y + 6) / 9 = (x - 7/2) / (-7/2)
-7/2 (y + 6) = 9 (x - 7/2)
-7/2 y - 21 = 9x - 63/2
2 (-7/2 y - 21) = 2 (9x - 63/2)
-7y - 42 = 18 x - 63
-18x - 7y - 42 + 63 = 0
-18x - 7y + 21 = 0
18x + 7y - 21 = 0