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Verified answer
H(t) = -6t² + 480th(t) akan maksimum untuk t yang memenuhi h'(t) = 0
h'(t) = -12t + 480
-12t + 480 = 0
-12t = -480
t = 40
Tinggi maksimum peluru, substitusi t ke h(t)
h(t) = -6t² + 480t
h(40) = -6(40)² + 480(40) = -9600 + 19200 = 9600
Tinggi maksimum peluru tersebut adalah 9600 meter