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usia ayah = A
usia adik = B
(A-3) = 5(B-3)+2
A-3 = 5B-15+2
A = 5B-10 .....[1]
2(B+5) = (A+5)-6
2B+10 = A-1
substitusi [1] didapat
2B+10 = 5B-10-1
2B+10 = 5B-11
3B = 21
B = 7
substitusi B=7 ke [1] didapat
A = 5(7)-10
A = 35-10=25
jadi usia ayah dan adik berturut-turut adalah 25 dan 7 tahun