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Verified answer
1/3+1/6+1/4 = 4/12+2/12+3/12= 9/12=3/41/rpengganti= 3/4
Rpengganti= 4/3=1,33
-Rangkaian Resisor
Dik : R₁ = 3 Ω
R₂ = 6 Ω
R₃ = 4 Ω
Dit : Rₚ = __ ?
Jwb : 1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃
1/Rₚ = ⅓ + ⅙ + ¼
1/Rₚ = (4 + 2 + 3) / 12
1/Rₚ = 9/12
Rₚ = 12/9 Ω
atau
Rₚ ≈ 1,33 Ω