Question

Tiga buah hambatan masing-masing dari 2ohm,5ohm,dan 10ohm di rangkai secara paralel.rangkaian hambatan ini di pasang pda sebuah sumber listrik yg mempunyai bda potensial sebesar 10volt.tentukan :(a.)besar hambatan penggantinya, (b.)kuat arus induk,dan (c)kuat arus pda masing-masing hambatan.tolong bantuin ya buat hari senin besok

Answer 1

Diket:
R1 = 2 ohm
R2 = 5 ohm
R3 = 10 ohm
V = 10 Volt
Dit:
a. Rp....?
b. Itotal...?
c. I masing2 hambatan.
Jawab
a. R utk rangkaian paralel
1/Rp = 1/R1 + 1/R2 + 1/R3
1/Rp = 1/2 + 1/5 + 1/10
1/Rp = 5/10 + 2/10 + 1/10
1/Rp = 8/10
Rp = 10/8
Rp = 5/4 = 1 1/4 = 1,25 ohm
,
b. Itotal = V/Rp
Itotal = 10/1,25
Itotal = 8A
,
c. I masing2 hambatan
I1 = V/R1 = 10/2 = 5A
I2 = V/R2 = 10/5 = 2A
I3 = V/R3 = 10/10 = 1A